2.4 Costs of Production - Class Notes
Contents
- Tuesday, March 23, 2020
- Quarantine Lecture 1
Overview
Today we cover costs and revenues before we put them together next class to solve the firm’s profit maximization problem.
Class Livestream/Lecture Videos
See the above video for a brief overview of Zoom.
Slides
Assignments: Exam 1 Corrections & Homework 3
You will have until the end of the semester (May 4) to turn in your corrections, however, I advise you to do them as soon as possible. See more from the online transition page for details.
Homework 3 is now due, via email, on Sunday, March 29, by 11:59PM. The answer key will be posted Monday, March 30.
Appendix
The Relationship Between Returns to Scale and Costs
There is a direct relationship between a technology’s returns to scaleIncreasing, decreasing, or constant
and its cost structure: the rate at which its total costs increaseAt a decreasing rate, at an increasing rate, or at a constant rate, respectively
and its marginal costs changeDecreasing, increasing, or constant, respectively
. This is easiest to see for a single input, such as our assumptions of the short run (where firms can change l but not ˉk):
q=f(ˉk,l)
Constant Returns to Scale:
Decreasing Returns to Scale
Increasing Returns to Scale
Cobb-Douglas Cost Functions
The total cost function for Cobb-Douglas production functions of the form
q=lαkβ
C(w,r,q)=[(αβ)βα+β+(αβ)−αα+β]wαα+βrβα+βq1α+β
If you take the first derivative of this (to get marginal cost), it is:
∂C(w,r,q)∂q=MC(q)=1α+β(wαα+βrβα+β)q(1α+β)−1
How does marginal cost change with increased output? Take the second derivative:
∂2C(w,r,q)∂q2=1α+β(1α+β−1)(wαα+βrβα+β)q(1α+β)−2
- If 1α+β>1, this is positive ⟹ decreasing returns to scale
- α+β<1 in the production function
- If 1α+β<1, this is negative ⟹ increasing returns to scale
- α+β>1 in the production function
- If 1α+β=1, this is constant ⟹ constant returns to scale
- α+β=1 in the production function
Example (Constant Returns)
Let q=l0.5k0.5.
C(w,r,q)=[(0.50.5)0.50.5+0.5+(0.50.5)−0.50.5+0.5]w0.50.5+0.5r0.50.5+0.5q10.5+0.5C(w,r,q)=[10.5+1−0.5]w0.5r0.5q0.5C(w,r,q)=w0.5r0.5q1
If w=9, r=25:
C(w=10,r=20,q)=90.5250.5q=3∗5∗q=15q
Marginal costs would be
MC(q)=∂C(q)∂q=15
Average costs would be
MC(q)=C(q)q=15qq=15
Example (Decreasing Returns)
Let q=l0.25k0.25.
C(w,r,q)=[(0.250.25)0.250.25+0.25+(0.250.25)−0.250.25+0.25]w0.250.25+0.25r0.250.25+0.25q10.25+0.25C(w,r,q)=[10.5+1−0.5]w0.5r0.5q2C(w,r,q)=w0.5r0.5q2
If w=9, r=25:
C(w=10,r=20,q)=90.5250.5q2=3∗5∗q2=15q2
Marginal costs would be
MC(q)=∂C(q)∂q=30q
Average costs would be
AC(q)=C(q)q=15q2q=15q