2.4 Costs of Production - Class Notes

Contents

Overview

Today we cover costs and revenues before we put them together next class to solve the firm’s profit maximization problem.

Class Livestream/Lecture Videos

See the above video for a brief overview of Zoom.

Slides

Assignments: Exam 1 Corrections & Homework 3

You will have until the end of the semester (May 4) to turn in your corrections, however, I advise you to do them as soon as possible. See more from the online transition page for details.

Homework 3 is now due, via email, on Sunday, March 29, by 11:59PM. The answer key will be posted Monday, March 30.

Appendix

The Relationship Between Returns to Scale and Costs

There is a direct relationship between a technology’s returns to scaleIncreasing, decreasing, or constant

and its cost structure: the rate at which its total costs increaseAt a decreasing rate, at an increasing rate, or at a constant rate, respectively

and its marginal costs changeDecreasing, increasing, or constant, respectively

. This is easiest to see for a single input, such as our assumptions of the short run (where firms can change l but not ˉk):

q=f(ˉk,l)

Constant Returns to Scale:

Decreasing Returns to Scale

Increasing Returns to Scale

Cobb-Douglas Cost Functions

The total cost function for Cobb-Douglas production functions of the form q=lαkβ

can be shown with some very tedious algebra to be:

C(w,r,q)=[(αβ)βα+β+(αβ)αα+β]wαα+βrβα+βq1α+β

If you take the first derivative of this (to get marginal cost), it is:

C(w,r,q)q=MC(q)=1α+β(wαα+βrβα+β)q(1α+β)1

How does marginal cost change with increased output? Take the second derivative:

2C(w,r,q)q2=1α+β(1α+β1)(wαα+βrβα+β)q(1α+β)2

Example (Constant Returns)

Let q=l0.5k0.5.

C(w,r,q)=[(0.50.5)0.50.5+0.5+(0.50.5)0.50.5+0.5]w0.50.5+0.5r0.50.5+0.5q10.5+0.5C(w,r,q)=[10.5+10.5]w0.5r0.5q0.5C(w,r,q)=w0.5r0.5q1

If w=9, r=25:

C(w=10,r=20,q)=90.5250.5q=35q=15q

Marginal costs would be

MC(q)=C(q)q=15

Average costs would be

MC(q)=C(q)q=15qq=15

Example (Decreasing Returns)

Let q=l0.25k0.25.

C(w,r,q)=[(0.250.25)0.250.25+0.25+(0.250.25)0.250.25+0.25]w0.250.25+0.25r0.250.25+0.25q10.25+0.25C(w,r,q)=[10.5+10.5]w0.5r0.5q2C(w,r,q)=w0.5r0.5q2

If w=9, r=25:

C(w=10,r=20,q)=90.5250.5q2=35q2=15q2

Marginal costs would be

MC(q)=C(q)q=30q

Average costs would be

AC(q)=C(q)q=15q2q=15q